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ว เคราะห ข_อสอบล_คก__
- 1. 3
3
10
:
1 10400 6
--- -- .
-------
2
3
7
4
5
- 2. 8
9 10
2 10
1 High
1 2 3 4 5 6 7 8 9 10
1 1 0 1 1 1 0 0 1 1 1 7
2 1 1 1 1 1 0 1 1 0 0 7
3 0 1 0 1 1 1 0 1 1 0 6
4 1 0 0 1 1 0 1 1 1 0 6
5 0 1 1 0 0 1 0 1 1 0 5
- 3. 3 3 3 4 4 4 2 5 4 3 35
2 Low
1 2 3 4 5 6 7 8 9 10
1 0 1 0 0 0 1 0 1 1 1 5
2 1 0 0 1 1 0 1 0 0 0 4
3 0 0 1 0 1 1 0 0 0 0 3
4 0 0 0 0 0 0 0 1 1 0 2
5 0 1 1 0 0 0 0 0 0 0 2
1 1 1 1 2 2 2 2 2 2 16
3 p r
H L p r q pq
1 3 1 0.20 0.20 0.80 0.1600
2 3 2 0.25 -0.20 0.75 0.1875
3 3 2 0.25 -0.20 0.75 0.1875
4 4 1 0.25 0.30 0.75 0.1875
5 4 2 0.30 0.20 0.70 0.2100
6 2 2 0.20 0 0.80 0.1600
7 2 1 0.15 -0.05 0.85 0.1275
8 5 2 0.35 0.30 0.65 0.2275
9 4 2 0.30 0.20 0.70 0.2100
10 1 1 0.10 0 0.90 0.0900
- 4. ∑pq =
1.7475
p r
p = 0.35
= 0.10
r = 0.30
= 0
SD
S² = ( 10 × 253 ) – ( 47² )
10 (10-1)
= 2530 – 2209 = 321
90 90
SD = 3.56
KR – 20
rtt = n [
n–1
1- ]
∑pq
S²
= [
10 1- ] 1.7475
9 3.56
= 1.11 × 0.68
= -0.20
- 5. H L
2 3 2 P = 0.25
- - r = -0.20
- 2
1 1
6 P = 0.25 r = 0.10
H L
2
2
2
H L
3 - 1 P = 0.25
- 1 r = -0.20
2 2
3 1
3 P = 0.25 r = 0.10
- 6. H
3 L 1
H L
2
3
3
H L
6 - - P = 0.20
4 2 r =0
- 2
1 1
6 P = 0.20 r =0
H
4 L 2
- 7. H L
2
6
6
H L
7 - 1 P = 0.15
- - r = -0.50
3 2
2 2
7 P = 0.15 r = 0.10
- 8. H L
2
7
7
H L
10 - 1 P = 0.10
- - r =0
2 2
3 2
10 P = 0.10 r =0
H L
- 9. 2
10
10
2
10
10
p r
5 5